Total number of one-one function possible from a set having 3 element to a set having 2 element is
- 3
- 2
- 0
- 6
- 0
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A function will said to be one one if Elements of set A has unique elements in set B. This is possible if number of elements of set A is >= No. Of elements in set B.
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Total number of one-one function possible from a set having 2 element to a set having 3 element is
- 3
- 2
- 0
- 6
- 6
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Let there is two elements A and B
Given, cardinality of A & B is 2 & 3.
Total number of one one function=n permutations M(nPm).
Therefore, 3P2 = 3!/(2-1)! = 6
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The relation R is defined on set A={1,2,3} by (x,y)∈R if x+y<7. Relation R is
- Reflexive
- Reflexive & Symmetric
- Reflexive, Symmetric & Transitive
- None of the above
- Reflexive, Symmetric & Transitive
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The relation R is defined on set A={1,2,3} by R={(x,y)∈R | x+y
- Reflexive & Symmetric
- Symmetric & Transitive
- Reflexive, Symmetric & Transitive
- None of the above
- Symmetric & Transitive
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Suppose X and Y are |X| and |Y| are their respective cardinalities. It is given that there are exactly 97 functions from Y to X. From this one can conclude that
- |X|=97, |Y|=1
- |X|=1, |Y|=97
- |X|=97, |Y|=97
- None of the above
- option1
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Given there is exactly 97 function from Y to X
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What is the possible number of reflexive relations on a set of 5 elements?
- 2^5
- 2^10
- 2^15
- 2^20
- 2^20
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Total number of a reflexive relation on a set contains n elements is 2^((n^2)- n).
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What is the possible number of reflexive relations on a set of 3 elements?
- 2^3
- 2^6
- 2^9
- 2^12
- 2^9
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Total number of a reflexive relation on a set contains n elements is 2^((n^2)- n).
Therefore For n=3: 2^((3^3)-3)=2^6
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Suppose that R1 and R1 are reflexive relations on a set A. Which of the following statements is correct?
- R₁∪ R₂ is reflexive and R₁U R₂ is irreflexive.
- R₁∪ R₂ is irreflexive and R₁U R₂ is reflexive.
- Both R₁ ∪ R₂ and R₁UR₂ are reflexive.
- Both R₁ R₂ and R₁U R₂ are irreflexive.
- Both R₁ ∪ R₂ and R₁U R₂ are reflexive.
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Let
A={1,2}
R1={(1,1),(2,2)} is reflexive on set A.
and, R2={(1,1),(2,2)} is reflexive on set A.
R1∪R2={(1,1),(2,2)}
R1∩R2={(1,1),(2,2)}
Therefore Both R1∪R2 and R1∩R2 are reflexive
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A relation R = {(1, 1),(2, 2),(3, 3)} defined in set A={1,2,3}. Identify the properties of relation R
- Reflexive & Symmetric
- Symmetric & Asymmetric
- Reflexive, Symmetric & Asymmetric
- Reflexive, Symmetric & Transitive
- Reflexive, Symmetric & Asymmetric
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A relation R = {(1, 1),(1, 2),(1, 3)}. Identify the properties of relation R
- Reflexive
- Transitive
- Reflexive, Symmetric
- Symmetric & Transitive
- Transitive
Clear All
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