QuizSagar
4 years ago Like 232906
Questions 823
Contests 7
Open circulatory system is found in
- Cat
- Human
- Bird
- Butterfly
- option4
Clear All
Open circulatory system found in butterfly, pumps blood into a cavity called a hemocoel where it surrounds the organs and then returns to the heart(s) through ostia (openings).
Loading...
Which one of these is not a plant excretory product? [Note- Post your answer in comment box.]
- Tanine
- Resin
- Latex
- Strach
- option4
Clear All
Loading...
\(\frac{sin63^\circ}{cos27^\circ} \) =
- \(\sqrt{3}\)
- 1
- 2
- 3
- option2
Clear All
Hint:- Change \(sin\theta\) to \(cos\theta \)we know \(sin\theta\) = \(cos(90^\circ-\theta)\) so \(sin63^\circ\) can be written as \(cos(90^\circ-63^\circ)\) = \(cos27^\circ\) Now, \(\frac{sin63^\circ}{cos27^\circ}\) =
\(\frac{cos(90^\circ-
Loading...
Predicate the output of the following problem if the input is "QuizSagar".
#include <stdio.h>
int main()
{
char s[100];
scanf("%[A-Z]s",s);
printf("%s",s);
return 0;
}
- QuizSagar
- QS
- Q
- S
- option2
Clear All
%[A-Z] is a scanset of CAPITAL alphabets A-Z, so scanf() accept only capital alphabets from above inputs "QuizSagar" so outputs will be QS.
The scanset is basically a specifier supported by scanf(). It is represented by %[].
Inside scanset we can specify
Loading...
Predicate the output of the following problem if the input is "QuizSagar".
#include <stdio.h>
int main()
{
char s[100];
scanf("%[A-Z,0-9]s",s);
printf("%s",s);
return 0;
}
- QuizSagar1
- QS
- QS1
- Q
- option3
Clear All
Accept only capital alphabets A-Z and digit from 0-9
Loading...
Predicate the output of the following problem if the input is "QuizSagar".
#include <stdio.h>
int main()
{
char s[100];
scanf("%[A-Z]s",s);
printf("%s",s);
return 0;
}
- QuizSagar
- QS1
- QS
- Q
- option3
Clear All
Loading...
If the circumfrence and the area of a circle are numerically equal, the diameter of the circle will be
- Π unit
- 2 unit
- 3Π unit
- 4 unit
- option4
Clear All
Loading...
If table R has only one candidate key, then which of the following is always true?
- R is in 2NF, but is not in 3NF
- R is in 2NF, but may not be in 3NF
- R is in 3NF, it is also in BCNF
- None of these
- option3
Clear All
if it is in 3NF then surely it will be in BCNF because to be a relation in 3NF not in BCNF atleast two compound keys are needed, so that proper set of one candidate key drives proper subset of other candidate key.[From external source]
Loading...
Relation R has atleast one simple candidate key and it is also given that R is in BCNF. Which of the following statement is true?
- R may or may not be in 4NF.
- R is surely in 4NF.
- R is BCNF but not 4NF.
- Cannot conclude to a statement.
- option2
Clear All
It is already mention that R is in BCNF and a simple candidate key is present. By availability of simple candidate key, it is guaranteed that that no multivalued attribute is present in the table. Because if some multivalued attributed is there in the tab
Loading...
\((a+b)(a-b)=\)
- \(a^2+b^2\)
- \(a^2-b^2\)
- \((a+b)^2\)
- \((a-b)^2\)
- option2
Clear All
Loading...